Let f (x) = i Using the centered 3-point formula for 1st derivatives: (x+1)3" f'(0) x -2.04061 using h = 0.1 f'(0) x -2.01004 using h = 0.05 Applying Richardson's extrapolation on the above values, we...

Extracted text: Let f (x) = i Using the centered 3-point formula for 1st derivatives: (x+1)3" f'(0) x -2.04061 using h = 0.1 f'(0) x -2.01004 using h = 0.05 Applying Richardson's extrapolation on the above values, we get a better approximation of f'(0) which is: 0.234256 -1.99985 0.249999 -0.499998