Let B = {b¡, following by filling in the blanks: b,} be a basis for a vector space V. You will be proving the ... If a subset {u,, ,} is linearly dependent in V, then the set of coordinate vectors...


Let B = {b¡,<br>following by filling in the blanks:<br>b,} be a basis for a vector space V. You will be proving the<br>...<br>If a subset {u,,<br>,} is linearly dependent in V, then the set of coordinate vectors<br>.... U<br>{{u, la [u,]} is linearly dependent in R

Extracted text: Let B = {b¡, following by filling in the blanks: b,} be a basis for a vector space V. You will be proving the ... If a subset {u,, ,} is linearly dependent in V, then the set of coordinate vectors .... U {{u, la [u,]} is linearly dependent in R". You need only write the word for each blank on our quiz, but be organized so I can grade your work. (a) If set of vectors {u,, u,} is linearly dependent in V, then there exist scalars c,…, (where at least one c; is non-zero), (b) such that cu¡ +c,u, + +c,u,=0, where the zero vector is in (с) Вy the of the coordinate mapping: | qu, + ... +c,u,=[qu,]a+ [c,u, =G[u,] ++c, ...+ u
(d) (Note: u, la is a vector in<br>(e) Because the coordinate mapping is one-to-one, and since 0b, +Ob, + -+0__= 0,,<br>(1) [0, la =<br>the zero vector in<br>(g) Thus c[u,]+<br>·+c, u,= 0 , the zero vector in<br>(this is obtained by

Extracted text: (d) (Note: u, la is a vector in (e) Because the coordinate mapping is one-to-one, and since 0b, +Ob, + -+0__= 0,, (1) [0, la = the zero vector in (g) Thus c[u,]+ ·+c, u,= 0 , the zero vector in (this is obtained by "taking [ ]g of both sides of the equation in part (b)). These are the same c; scalars from part (a)! (h) Therefore, the set of vectors is

Jun 05, 2022
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