Let
(a) Approximate ln(1 −) with a third degree Taylor polynomial expanded about= 0 Using this approximation, what value should you assign to(0)?
(b) Using MATLAB, plot() for −10−15≤≤ 10−15. What value does MATLAB assign to() forvery near zero? The interval where the function is zero is not symmetric about= 0. Why? Also, does this also explain why there are more oscillations on the right (> 0) than on the left (<>
(c) Using MATLAB, plot ln(1−) for −5×10−15≤≤ 5×10−15. The graph should resemble steps with the step containing= 0 corresponding to the value of ln(1) = 0. Asincreases from= 0, what determines the value of the first nonzero step? How do these steps explain the oscillations seen in the plot for part (b)?
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