LESSON 8 AC DISTRIBUTION SYSTEM Example 2.14: A Single-Phase AC Ring Main Distribution System, ABCA, turning in a clockwise direction, fed at Point A with 240 V, supplies the following loads: Load...

LESSON 8<br>AC DISTRIBUTION SYSTEM<br>Example 2.14: A Single-Phase AC Ring Main Distribution<br>System, ABCA, turning in a clockwise direction, fed at Point A<br>with 240 V, supplies the following loads:<br>Load Point<br>Load Current<br>Power Factor<br>B<br>75 A<br>0.875 lag<br>C<br>60 A<br>0.9 lag<br>• Calculate the Current in each section of the Distributor if the Total<br>Impedances of the various sections (go and return) are as follows:<br>ZBC =<br>(0.05 + j0. 1)<br>ZCA = (0.025 + j0.5) N<br>%3D<br>ZAB = (0.01 + j0.015) N<br>

Extracted text: LESSON 8 AC DISTRIBUTION SYSTEM Example 2.14: A Single-Phase AC Ring Main Distribution System, ABCA, turning in a clockwise direction, fed at Point A with 240 V, supplies the following loads: Load Point Load Current Power Factor B 75 A 0.875 lag C 60 A 0.9 lag • Calculate the Current in each section of the Distributor if the Total Impedances of the various sections (go and return) are as follows: ZBC = (0.05 + j0. 1) ZCA = (0.025 + j0.5) N %3D ZAB = (0.01 + j0.015) N

Jun 11, 2022

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LESSON 8 AC DISTRIBUTION SYSTEM Example 2.14: A Single-Phase AC Ring Main Distribution System, ABCA, turning in a clockwise direction, fed at Point A with 240 V, supplies the following loads: Load...

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