left tailed test n= 15, t = -2.46 use a table of t values to estimate p value for specified one mean t test.

Answered Same DayDec 20, 2021

Answer To: left tailed test n= 15, t = -2.46 use a table of t values to estimate p value for specified one mean...

Robert answered on Dec 20 2021

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note that degrees of freedom = d.f = n− 1 = 14
p-value is in direction of alternate hypothesis, therefore p-value is
P (t < −2.46) = T.DIST(−2.46, 14, TRUE) = 0.0137546112005121
⇒ 0.0138
Using t-table, we can observe that the p-value is between 0.01 and .025
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left tailed test n= 15, t = -2.46 use a table of t values to estimate p value for specified one mean t test.

Answer To: left tailed test n= 15, t = -2.46 use a table of t values to estimate p value for specified one mean...

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