Kinematics: Angular MotionXXXXXXXXXXSection: Problems11-1. The minute hand of a clock travels from the 12 to the 9, whereupon it is discovered that the clock is fast. The minute hand is turned...

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Kinematics: Angular Motion Section: Problems 11-1. The minute hand of a clock travels from the 12 to the 9, whereupon it is discovered that the clock is fast. The minute hand is turned back and now points at the 6. What is the angular distance and displacement of the hand in radians? 11-6. The handle of a winch is turned 70 revolutions in 1.5 minutes. Determine the angular speed in rad/s. 11-9. Starting from rest, a shaft accelerates uniformly to 800 rpm in 10 seconds. Determine the angular acceleration in rad/s2. 11-12. A rotating drive shaft decelerates uniformly from 900 rpm to 650 rpm in 6 seconds. Determine the angular deceleration and the total number of revolutions in the 6-second interval. 11-17. A flywheel accelerates for 8 seconds at 1.3 rad/s2 from a speed of 40 rpm. Determine (a) the total number of revolutions and (b) the final angular speed. 11-27. For the system shown in Figure P11–27, determine the angular acceleration of the wheel and the tangential velocity of point A. 11-40. Pulleys C and D in Figure P11–40 are fastened together. Weights A and B are supported by ropes wound around the pulleys as shown. If weight A is accelerating downward at 2 m/s2, determine (a) the angular acceleration of pulleys C and D and (b) the linear acceleration of weight B. 11-53. A point 150 mm from the center of rotation has a normal acceleration of 4000 m/s2. Determine the speed of rotation.
Answered Same DayJan 31, 2023

Answer To: Kinematics: Angular MotionXXXXXXXXXXSection: Problems11-1. The minute hand of a clock travels...

Baljit answered on Feb 01 2023
44 Votes
11.1
Total angular distance =Distance angular distance travelled by minute hand between ( 1
2 to 9 + 9 to 6)
So
Total angular distance= +
Total angular displacement=Distance between 12 and 6
Total angular displacement=
11.2
Handle turned in 70 revolution per 1.5 minutes
Angular distance in 1.5 mintutes==140
time in second= 1.5 *60=90

11.3
Since it starts from rest
so initial angular velocit
Since it makes
Final angular speed
time t =10 sec
Now we...
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