Java Code Only: There are two A, B players playing the game. Player A has a string on him, and Player B has a string on him. Both s and t consist of only small English letters and are of equal length....

Extracted text: Java Code Only: There are two A, B players playing the game. Player A has a string on him, and Player B has a string on him. Both s and t consist of only small English letters and are of equal length. A makes the first move, then B, then A, and so on. Before the start of the game, players know the contents of both the s and t strings. These players form one rope during the game. Initially, the character unit w is empty. In each move, the player removes any single letter from the alphabetical order in sequence and adds this letter anywhere (anywhere) to the letter unit (Note that uw is a unit of characters all the time, and you can insert letters or at the end. It is not an empty list where you can add character in any reference. Please refer to the Definitions for further specifications). If in any stage of the game, the character unit w is more than 1 length and is a palindrome, the player who made the last move wins. If even after the game is over (i.e., when both s and t have turned into empty strings), no one can make a rope for a palindrome, and then player B wins. Given the unit of the letters s, and t, find out which one in A, B will win the game, if both play well. Input 1 ab ab Output: B