It's a test correction I have to do. don't have to do number 1# only 2 to 7 doesn't have to look good since i have to rewrite in a paper, do it fast as you can plz

1) P(X≥3) = 0.18+0.16+0.07=0.41
2) Expected gain = 1/18(15+(-1)(17/18) = -2/18 =-1/9. This is loss because of negative sign.
3) X is N(2000,500)
N=80
Hence sample std dev = 500/sqrt 80
X bar is N(2000, 55.9017)
P(X bar >2150)=0.003645
4) X no of students who read is binomial with n =8 and p = 0.66: q= 0.34
a) P(x=5) = 8C5 (0.66)^5 (0.34)^3 = 0.27564
b) P(X>6) = P(7)+P(8)=0.1484+0.0360=0.1843
c) P(x=8) = 0.0360
Hence this is unusual as prob...