It is very important that a certain solution in a chemical process have a pH of 8.30. The method used gives measurements which are approximately normally distributed about the actual pH of the solution with a known standard deviation of 0.020. We decide to use 5% as the critical level of significance.
a) Suppose a single determination shows pH of 8.32. The null hypothesis is that the true pH is 8.30 (H0: pH = 8.30). The alternative hypothesis isHa: pH ≠8.30 (this is a two-sided test because there is no indication that changes in only one direction are important).
b) Suppose that now our sample consists of 4 determinations giving values of 8.31, 8.34, 8.32, 8.31. The sample mean isx1 = 8.32.
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