It is reported that the average American eats out at a restaurant 5.9 times per week. A random sample of 40 Americans showed that the average amount of times they ate out at a restaurant per week was...


It is reported that the average American eats out at a restaurant 5.9 times per week. A random sample of 40 Americans showed that the average amount of times they ate out at a restaurant per week was 5.1 times with a standard deviation of 1.7.  Is there enough evidence at the 5% level that the average American eats out less than 5.9 times per week?


What is the set up for the problem?:


a) u = 5.1, x-bar = 5.9, o = 1.7, SE = 1.7/40 = 0.0425, z-score = 2.98, p-value: 0.025


b) u = 5.9, x-bar = 5.1, o = 1.7, SE = 1.7/sqrt(40) = 0.2688, z-score = -2.98, p-value: 0.0025


c) u = 5.9, x-bar = 5.1, o = 1.7, SE = 1.7/sqrt(40) = 0.2688, z-score = 2.98, p-value: 2.5


d) u = 5.1, x-bar = 5.9, o = 1.7, SE = 1.7/40 = 0.0425, z-score = -2.98, p-value: 0.0025



Jun 08, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here