It is decided to extract A from a feed containing 20 mol % A and 80 mol% B in two ideal cross current stages as shown Y* = 1.5 X below using equal amount of pure solvent where. X = moles of A per mole...


It is decided to extract A from a feed<br>containing 20 mol % A and 80 mol% B in<br>two ideal cross current stages as shown Y* = 1.5 X<br>below using equal amount of pure solvent where. X = moles of A per mole of B in raffinate Y * = moles<br>C in each stage.<br>Components B and C are immiscible. 60% of A in the feed<br>is extracted in Stage 1. The equilibrium relation is given by<br>of A per mole of C in extract in equilibrium with raffinate.<br>Selvent<br>Solvent<br>The mol % of A in raffinate from Stage 2 is<br>off to second decimal place).<br>(rounded<br>Feed<br>Raffinate 1<br>Raffinate 2<br>Stage 1<br>Stage 2<br>Extract 1<br>Extract 2<br>

Extracted text: It is decided to extract A from a feed containing 20 mol % A and 80 mol% B in two ideal cross current stages as shown Y* = 1.5 X below using equal amount of pure solvent where. X = moles of A per mole of B in raffinate Y * = moles C in each stage. Components B and C are immiscible. 60% of A in the feed is extracted in Stage 1. The equilibrium relation is given by of A per mole of C in extract in equilibrium with raffinate. Selvent Solvent The mol % of A in raffinate from Stage 2 is off to second decimal place). (rounded Feed Raffinate 1 Raffinate 2 Stage 1 Stage 2 Extract 1 Extract 2

Jun 07, 2022
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