Interpreting computer output: The following output from MINITAB presents the results of a hypothesis test. Test of μ = 232 vs > 232 The assumed standard deviation = 39 N Mean SE Mean 95% Lower Bound Z P 52 242.41 5.41 233.51 1.92 0.027 (a) What are the null and alternate hypotheses?(b) What is the value of the test statistic?(c) What is theP-value?(d) Do you reject H0 at the =α0.05 level?(e) Do you reject H0 at the =α0.01 level?

Interpreting computer output: The following output from MINITAB presents the results of a hypothesis test. Test of μ = 232 vs > 232 The assumed standard deviation = 39 N Mean SE Mean 95% Lower Bound Z...

Interpreting computer output: The following output from MINITAB presents the results of a hypothesis test.

Test of μ = 232 vs > 232
The assumed standard deviation = 39
N	Mean	SE Mean	95% Lower Bound	Z	P
52	242.41	5.41	233.51	1.92	0.027

(a) What are the null and alternate hypotheses?

(b) What is the value of the test statistic?

(d) Do you reject

at the

=α0.05

level?

(e) Do you reject

at the

=α0.01

level?

Jun 01, 2022