INPUT: All integer, no validation or ranges needed. Although the user can enter whatever numbers they wish, consider a more 'realistic' scenario for input, e.g., 1. Input production cost (the cost to...


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INPUT:<br>All integer, no validation or ranges needed.<br>Although the user can enter whatever numbers they wish, consider a more<br>'realistic' scenario for input, e.g.,<br>1. Input production cost (the cost to management of setting up the play)<br>Keep is sensible – maximum of £5000 maybe – but no validation needed;<br>Keep it sensible – is a production costs of £100 realistic?<br>2. Input the price of one seat in band-A<br>(band-A price is double band-B price)<br>3. Input the price of one seat in band-B<br>(band-B is half the price of band-A price)<br>Keep band-A and band-B seat prices sensible:<br>Maybe keep them below £100 but no validation needed<br>PROCESS:<br>Part-1: Full house: All seats sold – no empty seats<br>a) How many days to break-even based on all seats being sold<br>Part-2: Part house: Only some seats sold – there are empty seats<br>a) How many days for the production to break even if only some seats are sold<br>Randomly allocate seats across band-A and band-B:<br>Use the total as an expected average for each part-house:<br>i.e.<br>if you get, say 5 seats sold in band-A and 4 seats sold in band-B then the part-<br>house total for one night will be:<br>(5 * 20) + (4 * 10) = 100 +40 = £140<br>You can assume £140 is the average for every part-house night – there is no<br>need to repeat the randomisation and then take an overall average<br>

Extracted text: INPUT: All integer, no validation or ranges needed. Although the user can enter whatever numbers they wish, consider a more 'realistic' scenario for input, e.g., 1. Input production cost (the cost to management of setting up the play) Keep is sensible – maximum of £5000 maybe – but no validation needed; Keep it sensible – is a production costs of £100 realistic? 2. Input the price of one seat in band-A (band-A price is double band-B price) 3. Input the price of one seat in band-B (band-B is half the price of band-A price) Keep band-A and band-B seat prices sensible: Maybe keep them below £100 but no validation needed PROCESS: Part-1: Full house: All seats sold – no empty seats a) How many days to break-even based on all seats being sold Part-2: Part house: Only some seats sold – there are empty seats a) How many days for the production to break even if only some seats are sold Randomly allocate seats across band-A and band-B: Use the total as an expected average for each part-house: i.e. if you get, say 5 seats sold in band-A and 4 seats sold in band-B then the part- house total for one night will be: (5 * 20) + (4 * 10) = 100 +40 = £140 You can assume £140 is the average for every part-house night – there is no need to repeat the randomisation and then take an overall average
OUTPUT:<br>Minimum dashboard example<br>(Preferably o/p the 2-d list showing all seats sold)<br>Full house costs:<br>£<br>Production cost<br>3000<br>Full house revenue:<br>Band-A 10 seats at £20.00 per seat<br>Band-B 10 seats at £10.00 per seat<br>200<br>100<br>Revenue total for one full house<br>300<br>Number of shows to break-even<br>3000 / 300 = 10 (round up)<br>%3D<br>(Preferably o/p the 2-d list showing what seats were sold)<br>Part-house costs:<br>£<br>Production cost<br>3000<br>Part-house revenue:<br>Band-A 5 seats at £20.00 per seat<br>Band-B 4 seats at £10.00 per seat<br>Revenue total for ono part house<br>100<br>40<br>140<br>Number of shows to break-even<br>3000 / 140 = 21.42= 22 (round up)<br>Notes:<br>Useful enhancements to the output will be considered.<br>Implementation that does not meet the full specification may be considered a<br>reasonable attempt.<br>Mark scheme:<br>Analysis and Design 25%<br>Implementation 50%<br>Pseudocode 25%<br>

Extracted text: OUTPUT: Minimum dashboard example (Preferably o/p the 2-d list showing all seats sold) Full house costs: £ Production cost 3000 Full house revenue: Band-A 10 seats at £20.00 per seat Band-B 10 seats at £10.00 per seat 200 100 Revenue total for one full house 300 Number of shows to break-even 3000 / 300 = 10 (round up) %3D (Preferably o/p the 2-d list showing what seats were sold) Part-house costs: £ Production cost 3000 Part-house revenue: Band-A 5 seats at £20.00 per seat Band-B 4 seats at £10.00 per seat Revenue total for ono part house 100 40 140 Number of shows to break-even 3000 / 140 = 21.42= 22 (round up) Notes: Useful enhancements to the output will be considered. Implementation that does not meet the full specification may be considered a reasonable attempt. Mark scheme: Analysis and Design 25% Implementation 50% Pseudocode 25%
Jun 09, 2022
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