In this exercise we outline a proof of the following theorem: A subset of is open iff it is the union of countably many disjoint open intervals in . (a) Let S be a nonempty open subset of . For each...


In this exercise we outline a proof of the following theorem: A subset of

is open iff it is the union of countably many disjoint open intervals in
.


(a) Let S be a nonempty open subset of
. For each x ∈ S, let Ax
= {a ∈

: (a, x ] ⊆ S } and let Bx
= {b ∈ R : [x, b) ⊆ S }. Use the fact that S is open to show that Ax
and Bx
are both nonempty.


(b) If Ax
is bounded below, let ax
= inf Ax. Otherwise, let ax
= −
. If Bx
is bounded above, let bx
= sup Bx; otherwise, let bx
=
. Show that ax
∉ S and bx
∉ S.


(c) Let
Ix
be the open interval (ax
, bx). Clearly, x ∈ I x. Show that I x ⊆ S. (Hint: Consider two cases for y ∈ I x : y <> x.)


(d) Show that S = ∪x


S

Ix.


(e) Show that the intervals {Ix
: x ∈ S} are pairwise disjoint. That is, suppose x, y ∈ S with x ≠ y. If Ix
∩ Iy
≠ ∅, show that Ix
= Iy.


(f) Show that the set of distinct intervals {I x : x ∈ S} is countable.



May 05, 2022
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