Please am preparing for my exam. Try to simplify as much as possible. This is a previous year exam sat by the same Professor. But I don't really get answers after solving the problem. Would you please...


Please am preparing for my exam. Try to simplify as much as possible. This is a previous year exam sat by the same Professor. But I don't really get answers after solving the problem. Would you please try to solve it and circle the correct answers from the questions given below the figure. What is the trick/underlying idea that I should use to tackle a similar problem?


In the network of Figure, determine<br>R<br>-jXc<br>1<br>160<br>j2 0<br>100<br>V.<br>20<br>30<br>-j9 a<br>Where: V1 = 50<0° V; R=1 Q; Xc=10<br>8- The current I.<br>A) (11.85 +j11.0) A<br>C) (12.77 +j11.44) A<br>B) (14.1 +j12.58) A<br>D) (20.43 +j18.3)A<br>9- The current in the 2 Q resistance.<br>A) (6.1 + j6.78) A<br>C) (6.73 + j7.5) A<br>B) (9.79 +j10.85) A<br>D) (5.65 +j6.5) A<br>10- The current in the 3 Q resistance.<br>A) (6.52 + j7.23) A<br>C) (3.77 +j 4.33)A<br>B) (4.48 +j4.97) A<br>D) (4.1 + j4.5) A<br>11- The current in the 10Q resistance.<br>A) (2.84 + j0.15) A<br>C) (2.43 + j0.17) A<br>B) (2.58 + j0.13) A<br>D) (4.13 + j0.21) A<br>12- The voltage at node 1 (parallel circuit)<br>A) (25.79 +jl.33) V<br>C) (41.27 + j2.13) V<br>B) (24.3 + j1.7) V<br>D) (28.37 + j1.47) V<br>13- The complex power for the (3 – j2) Q impedance.<br>A) (134.52 - j134.52)VA<br>C) (284.6 - 284.6) VÀ<br>B) (111.18 - j111.18)VA<br>D) (98.9 -j98.9) VA<br>

Extracted text: In the network of Figure, determine R -jXc 1 160 j2 0 100 V. 20 30 -j9 a Where: V1 = 50<0° v;="" r="1" q;="" xc="10" 8-="" the="" current="" i.="" a)="" (11.85="" +j11.0)="" a="" c)="" (12.77="" +j11.44)="" a="" b)="" (14.1="" +j12.58)="" a="" d)="" (20.43="" +j18.3)a="" 9-="" the="" current="" in="" the="" 2="" q="" resistance.="" a)="" (6.1="" +="" j6.78)="" a="" c)="" (6.73="" +="" j7.5)="" a="" b)="" (9.79="" +j10.85)="" a="" d)="" (5.65="" +j6.5)="" a="" 10-="" the="" current="" in="" the="" 3="" q="" resistance.="" a)="" (6.52="" +="" j7.23)="" a="" c)="" (3.77="" +j="" 4.33)a="" b)="" (4.48="" +j4.97)="" a="" d)="" (4.1="" +="" j4.5)="" a="" 11-="" the="" current="" in="" the="" 10q="" resistance.="" a)="" (2.84="" +="" j0.15)="" a="" c)="" (2.43="" +="" j0.17)="" a="" b)="" (2.58="" +="" j0.13)="" a="" d)="" (4.13="" +="" j0.21)="" a="" 12-="" the="" voltage="" at="" node="" 1="" (parallel="" circuit)="" a)="" (25.79="" +jl.33)="" v="" c)="" (41.27="" +="" j2.13)="" v="" b)="" (24.3="" +="" j1.7)="" v="" d)="" (28.37="" +="" j1.47)="" v="" 13-="" the="" complex="" power="" for="" the="" (3="" –="" j2)="" q="" impedance.="" a)="" (134.52="" -="" j134.52)va="" c)="" (284.6="" -="" 284.6)="" và="" b)="" (111.18="" -="" j111.18)va="" d)="" (98.9="" -j98.9)="">

Jun 11, 2022
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