In the circuit of Figure P6.9: R = 1.3 k2 R2 = 1.9 k2 C = 0.5182 µF Determine: a. How the voltage transfer function V.(jo) V.(jo) Hy(j») = behaves at extremes of high and low frequencies. b. An...


In the circuit of Figure P6.9:<br>R = 1.3 k2<br>R2 = 1.9 k2<br>C = 0.5182 µF<br>Determine:<br>a. How the voltage transfer function<br>V.(jo)<br>V.(jo)<br>Hy(j») =<br>behaves at extremes of high and low frequencies.<br>b. An expression for the voltage transfer function and<br>show that it can be manipulated into the form<br>H.<br>H,(jo) =TFjf(@)<br>

Extracted text: In the circuit of Figure P6.9: R = 1.3 k2 R2 = 1.9 k2 C = 0.5182 µF Determine: a. How the voltage transfer function V.(jo) V.(jo) Hy(j») = behaves at extremes of high and low frequencies. b. An expression for the voltage transfer function and show that it can be manipulated into the form H. H,(jo) =TFjf(@)
where<br>R2<br>H. =<br>f(ω) -<br>wR¡R2C<br>R + R2<br>R1 + R2<br>c. The frequency at which f(@) = 1 and the value of<br>H, in decibels.<br>1,(j) R,<br>I(ja)<br>ww<br>V(jo)<br>c+R V(ja)<br>

Extracted text: where R2 H. = f(ω) - wR¡R2C R + R2 R1 + R2 c. The frequency at which f(@) = 1 and the value of H, in decibels. 1,(j) R, I(ja) ww V(jo) c+R V(ja)

Jun 10, 2022
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