In the circuit given below, Cin = Cb = 4.7 µF, CL = 10 nF, R1 = 68 kN, R2 = 22 k2, RD = 2.2 kN, RS = 112 Q and f = 10 kHz. In this case, find the lower and upper corner frequencies of the circuit....


In the circuit given below, Cin = Cb = 4.7 µF, CL = 10 nF, R1 = 68 kN, R2 = 22 k2, RD = 2.2 kN, RS = 112 Q and f = 10 kHz. In this case, find the lower and upper<br>corner frequencies of the circuit.<br>Note-1: The voltage gain in the middle band frequency is AvidB) = 27 dB.<br>Note-2: The gain of the circuit is given as below for A = 0.<br>(Rp//SCL<br>sCinRin<br>1 + sCinRin (1 + sC_Rp)(sC„Rs + (1+ gmRs))<br>-ImRp (1+ sC,Rs)<br>Rin<br>1<br>1<br>Rin +<br>sCin Im<br>1<br>+ (Rs// 5C<br>R1<br>RD<br>Vout<br>D<br>VDD<br>CL<br>Cin<br>M1<br>Vin<br>G<br>12<br>S<br>V1<br>+<br>R2<br>RS<br>Cb<br>O a. fs1 = 0 Hz, fs2 = 544,22 Hz, fp1 = 2.04 Hz, fp2 = 7.23 kHz, and fp3 = 1164,76 Hz<br>O b. fs1 = 0 Hz, fs2 = 241,88 Hz, fp1 = 1,63 Hz, fp2 = 5,78 kHz, and fp3 = 517,67 Hz<br>O c. fs1 = 0 Hz, fs2 = 302,35 Hz, fp1 = 1,63 Hz, fp2 = 5,78 kHz, and fp3 = 647,09 Hz<br>O d. fs1 = 0 Hz, fs2 = 362,82 Hz, fp1 = 2.04 Hz, fp2 = 7.23 kHz, and fp3 = 776,51 Hz<br>O e. fs1 = 0 Hz, fs2 = 483,75 Hz, fp1 = 2.04 Hz, fp2 = 7.23 kHz, and fp3 = 1035,34 Hz<br>O f. fs1 = 0 Hz, fs2 = 181,41 Hz, fp1 = 2.04 Hz, fp2 = 7.23 kHz, and fp3 = 388,25 Hz<br>O g. fs1 = 0 Hz, fs2 = 181,41 Hz, fp1 = 1,22 Hz, fp2 = 4,34 kHz, and fp3 = 388,25 Hz<br>O h. fs1 = 0 Hz, fs2 = 302,35 Hz, fp1 = 2.04 Hz, fp2 = 7.23 kHz, and fp3 = 647,09 Hz<br>O i. fs1 = 0 Hz, fs2 = 423,28 Hz, fp1 = 2.04 Hz, fp2 = 7.23 kHz, and fp3 = 905,93 Hz<br>O j. fs1 = 0 Hz, fs2 = 241,88 Hz, fp1 = 2.04 Hz, fp2 = 7.23 kHz, and fp3 = 517,67 Hz<br>수<br>

Extracted text: In the circuit given below, Cin = Cb = 4.7 µF, CL = 10 nF, R1 = 68 kN, R2 = 22 k2, RD = 2.2 kN, RS = 112 Q and f = 10 kHz. In this case, find the lower and upper corner frequencies of the circuit. Note-1: The voltage gain in the middle band frequency is AvidB) = 27 dB. Note-2: The gain of the circuit is given as below for A = 0. (Rp//SCL sCinRin 1 + sCinRin (1 + sC_Rp)(sC„Rs + (1+ gmRs)) -ImRp (1+ sC,Rs) Rin 1 1 Rin + sCin Im 1 + (Rs// 5C R1 RD Vout D VDD CL Cin M1 Vin G 12 S V1 + R2 RS Cb O a. fs1 = 0 Hz, fs2 = 544,22 Hz, fp1 = 2.04 Hz, fp2 = 7.23 kHz, and fp3 = 1164,76 Hz O b. fs1 = 0 Hz, fs2 = 241,88 Hz, fp1 = 1,63 Hz, fp2 = 5,78 kHz, and fp3 = 517,67 Hz O c. fs1 = 0 Hz, fs2 = 302,35 Hz, fp1 = 1,63 Hz, fp2 = 5,78 kHz, and fp3 = 647,09 Hz O d. fs1 = 0 Hz, fs2 = 362,82 Hz, fp1 = 2.04 Hz, fp2 = 7.23 kHz, and fp3 = 776,51 Hz O e. fs1 = 0 Hz, fs2 = 483,75 Hz, fp1 = 2.04 Hz, fp2 = 7.23 kHz, and fp3 = 1035,34 Hz O f. fs1 = 0 Hz, fs2 = 181,41 Hz, fp1 = 2.04 Hz, fp2 = 7.23 kHz, and fp3 = 388,25 Hz O g. fs1 = 0 Hz, fs2 = 181,41 Hz, fp1 = 1,22 Hz, fp2 = 4,34 kHz, and fp3 = 388,25 Hz O h. fs1 = 0 Hz, fs2 = 302,35 Hz, fp1 = 2.04 Hz, fp2 = 7.23 kHz, and fp3 = 647,09 Hz O i. fs1 = 0 Hz, fs2 = 423,28 Hz, fp1 = 2.04 Hz, fp2 = 7.23 kHz, and fp3 = 905,93 Hz O j. fs1 = 0 Hz, fs2 = 241,88 Hz, fp1 = 2.04 Hz, fp2 = 7.23 kHz, and fp3 = 517,67 Hz 수

Jun 11, 2022
SOLUTION.PDF

Get Answer To This Question

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here