In parallelogram ABCD, point S is the intersection point of its diagonals. The perimeter of ACDS is 5.6 cm smaller than the perimeter of ABCS. The angle bisector of ZBAD intersects segment BC in point...

In parallelogram ABCD, point S is the intersection point of its diagonals. The perimeter of ACDS is 5.6 cm smaller<br>than the perimeter of ABCS. The angle bisector of ZBAD intersects segment BC in point M. Find the lengths of<br>sides of the parallelogram if BM|: |MC = 7:4. (Solve this task without using Trigonometry)<br>

Extracted text: In parallelogram ABCD, point S is the intersection point of its diagonals. The perimeter of ACDS is 5.6 cm smaller than the perimeter of ABCS. The angle bisector of ZBAD intersects segment BC in point M. Find the lengths of sides of the parallelogram if BM|: |MC = 7:4. (Solve this task without using Trigonometry)

Jun 04, 2022

SOLUTION.PDF

Sun	Mon	Tue	Wed	Thu	Fri	Sat
30	31	1	2	3	4	5
6	7	8	9	10	11	12
13	14	15	16	17	18	19
20	21	22	23	24	25	26
27	28	29	30	1	2	3

In parallelogram ABCD, point S is the intersection point of its diagonals. The perimeter of ACDS is 5.6 cm smaller than the perimeter of ABCS. The angle bisector of ZBAD intersects segment BC in point...

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