In Example 8.2, it was assumed that no condensate is produced in the line. Using the same operating conditions, and the dosages given in the example, if 0.02 GPM (2.83 m3 liquid/106 Nm3 gas) of...

In Example 8.2, it was assumed that no condensate is produced in the line. Using the same operating conditions, and the dosages given in the example, if 0.02 GPM (2.83 m3 liquid/106 Nm3 gas) of condensate (molar mass = 80, SpGr = 0.65) forms in the line, estimate the additional amount (lbm per MMscf, g per 103 Nm3 ) of methanol required to account for loss in condensate.