In Calc. 3 applications, polar coordinates always obey: (a) r = Vx2 + y² > 0 (b) 0


please explain mathematically


In Calc. 3 applications, polar coordinates always obey:<br>(a) r = Vx2 + y² > 0<br>(b) 0<0 <2т.<br>tan (0) = y/x. Examine the Quadrants.<br>If (x, y) = (-V3, 1) , then findr and 0.<br>This must be in Quadrant II.<br>r =<br>+ 12 = V3 +1 = 2<br>1<br>tan (0)<br>/3)<br>Normally, this would give us -7/6, but this in Quadrant IV.<br>If we add 180°, we end up in Quad. II and 0 = 57/6.<br>

Extracted text: In Calc. 3 applications, polar coordinates always obey: (a) r = Vx2 + y² > 0 (b) 0<0><2т. tan="" (0)="y/x." examine="" the="" quadrants.="" if="" (x,="" y)="(-V3," 1)="" ,="" then="" findr="" and="" 0.="" this="" must="" be="" in="" quadrant="" ii.="" r="+" 12="V3" +1="2" 1="" tan="" (0)="" 3)="" normally,="" this="" would="" give="" us="" -7/6,="" but="" this="" in="" quadrant="" iv.="" if="" we="" add="" 180°,="" we="" end="" up="" in="" quad.="" ii="" and="" 0="">

Jun 03, 2022
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