In an integer programming problem minx≥0{cx | Ax ≥ b, x integral},
the Lagrangean relaxation is
θ(u) = min x≥0
{(c − uA)x + ub | x integral}
Show that when the Lagrangean relaxation can be solved as a linear programming problem, the Lagrangean dual gives the same bound as the linear
programming relaxation. That is, if
{(c − uA)x + ub}
then maxu≥0{θ(u)} = minx≥0{cx | Ax ≥ b}.
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