In an efiort co counteract student cheating, the professor of a large class created four versions of a midterm exam, distributing the four versions among the 344 students in the class. After the exam,...

Extracted text: In an efiort co counteract student cheating, the professor of a large class created four versions of a midterm exam, distributing the four versions among the 344 students in the class. After the exam, 4 students from the class got together and petitioned to nullify the results on the grounds that the four versions were not equal in difficulty. To investigate the students' assertion, the professor examined the means and variances of the scores on the different versions of the exam, obtaining the following information (the exam had 200 possible points). Sample Sample Sample size Group mean variance Version A 86 157.1 439.4 Version B 86 151.2 302.8 Version C 86 158.4 352.0 Version D 86 152.9 392.8 Send data to calculator Send data to Excel Taking the 86 scores for each version of the exam as a sample of scores for that version, the professor performed a one-way, independent-samples ANOVA test of the equality of the population mean scores for the four versions. Answer the following, carrying your intermediate computations to at least three decimal places and rounding your responses to at least one decimal place. (a) What is the value of the mean square for treatments (the "between groups" mean square) that would be reported in the ANOVA test? (b) What is the value of the mean square for error (the "within groups" mean square) that would be reported in the ANOVA test?