In a survey of 1380 households, 1155 families said that they eat out at least once a week. What is the percent margin of error for the proportion of families who eat out at least once a week? n = 1380...

In a survey of 1380 households, 1155 families said that they eat out at least once a week.   What is the percent margin of error for the proportion of families who eat out at least once a week?

n = 1380

p =

(1-p) =

E=1.96

Error in decimal form =  _______ (round to three decimal places)

Error in percent form =  _______ ( round to the nearest tenth of a percent)