In a study of children with a particular disorder, parents were asked to rate their child on a variety of items related to how well their child performs different tasks. One item was "Has difficulty...

1 answer below »
In a study of children with a particular disorder, parents were asked to rate their child on a variety of items related to how well their child performs different tasks. One item was "Has difficulty organizing work," rated on a five-point scale of 0 to 4 with 0 corresponding to "not at all" and 4 corresponding to "very much." The mean rating for 284 boys with the disorder was reported as 2.21 with a standard deviation of 1.08. (Round your answers to four decimal places.)
Compute the 90% confidence interval.

Answered Same DayDec 26, 2021

Answer To: In a study of children with a particular disorder, parents were asked to rate their child on a...

Robert answered on Dec 26 2021
122 Votes
90% CI for µ using Normal dist
Sample Mean = x = 2.21
Since sample size is large, sample standard
deviation can be taken as an approx-
imation of population standard deviation.
Population Standard deviation = σ = 1.08
Sample Size = n = 284
Significance level = α = 1− Confidence = 1− 0.9 = 0.1
The Critical Value = zα/2 = z0.05 = 1.645 (From z table , using...
SOLUTION.PDF

Answer To This Question Is Available To Download

Related Questions & Answers

More Questions »

Submit New Assignment

Copy and Paste Your Assignment Here