In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6989 subjects randomly selected from an online group involved with ears. There were 1306 surveys...

need the last part. is it right?

Extracted text: In a study of cell phone usage and brain hemispheric dominance, an Internet survey was e-mailed to 6989 subjects randomly selected from an online group involved with ears. There were 1306 surveys returned. Use a 0.01 significance level to test the claim that the return rate is less than 20%. Use the P-value method and use the normal distribution as an approximation to the binomial distribution. Identify the null hypothesis and alternative hypothesis. O A. Ho: p= 0.2 Св. Но: р0.2 H4: p>0.2 H1:p<0.2 o="" d.="" ho:p="0.2" o="" c.="" ho:=""><0.2 h4:p="0.2" h1:p#0.2="" o="" e.="" ho:="" p="">0.2 H,:p= 0.2 OF. Ho: p#0.2 H1:p= 0.2 The test statistic is z = - 2.75. (Round to two decimal places as needed.) The P-value is 0.003 (Round to three decimal places as needed.) Because the P-value is less than the significance level, reject the null hypothesis. There is insufficient evidence to support the claim that the return rate is less than 20%.