In a sales effectiveness seminar, a group of sales representatives tried two approaches to selling a customer a new automobile: the aggressive approach and the passive approach. For 1160 customers,...


In a sales effectiveness seminar, a group of sales representatives tried two approaches to selling a customer a new automobile: the aggressive approach and the passive approach. For 1160 customers, the following record was kept:






























SaleNo SaleRow Total
Aggressive260320580
Passive466114580
Column Total7264341160


Suppose a customer is selected at random from the 1160 participating customers. Let us use the following notation for events:A = aggressive approach,Pa = passive approach,S = sale,N = no sale. So,P(A) is the probability that an aggressive approach was used, and so on.


1. Compute
P(S),P(S |A), andP(S |Pa). (Enter your answers as fractions.)


P(S) = ___


P(S |A) = ___


P(S |Pa) = ___


2. Are the events
S = sale andPa
= passive approach independent? Explain.

a. No. The two events cannot occur together.

b. Yes.
P(S) =P(S |Pa).

c. No.
P(S) ≠P(S |Pa).

d. Yes. The two events can occur together.



(c) ComputeP(A and S) andP(Pa and S). (Enter your answers as fractions.)


P(A and S) = ______


P(Pa and S) = _____

In a sales effectiveness seminar, a group of sales representatives tried two approaches to selling a customer a new automobile: the aggressive approach and the passive approach. For 1160<br>customers, the following record was kept:<br>Sale<br>No Sale<br>Row Total<br>Aggressive<br>260<br>320<br>580<br>Passive<br>466<br>114<br>580<br>Column Total<br>726<br>434<br>1160<br>Suppose a customer is selected at random from the 1160 participating customers. Let us use the following notation for events: A = aggressive approach, Pa = passive approach, S = sale, N<br>= no sale. So, P(A) is the probability that an aggressive approach was used, and so on.<br>(a) Compute P(S), P(S | A), and P(S | Pa). (Enter your answers as fractions.)<br>P(S) = 5/8<br>P(S | A) =<br>P(S | Pa) =<br>(b) Are the events S = sale and Pa = passive approach independent? Explain.<br>O No. The two events cannot occur together.<br>Yes. P(S) = P(S | Pa).<br>O No. P(S) * P(S | Pa).<br>O Yes. The two events can occur together.<br>(c) Compute P(A and S) and P(Pa and S). (Enter your answers as fractions.)<br>P(A and S) =<br>P(Pa and S) =<br>

Extracted text: In a sales effectiveness seminar, a group of sales representatives tried two approaches to selling a customer a new automobile: the aggressive approach and the passive approach. For 1160 customers, the following record was kept: Sale No Sale Row Total Aggressive 260 320 580 Passive 466 114 580 Column Total 726 434 1160 Suppose a customer is selected at random from the 1160 participating customers. Let us use the following notation for events: A = aggressive approach, Pa = passive approach, S = sale, N = no sale. So, P(A) is the probability that an aggressive approach was used, and so on. (a) Compute P(S), P(S | A), and P(S | Pa). (Enter your answers as fractions.) P(S) = 5/8 P(S | A) = P(S | Pa) = (b) Are the events S = sale and Pa = passive approach independent? Explain. O No. The two events cannot occur together. Yes. P(S) = P(S | Pa). O No. P(S) * P(S | Pa). O Yes. The two events can occur together. (c) Compute P(A and S) and P(Pa and S). (Enter your answers as fractions.) P(A and S) = P(Pa and S) =
Jun 03, 2022
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