In 7 =(-0.6x + 2.6.x – 2x1) +(1– x¡)(-1,8x +5.2x, - 2) In 7, =1.2x - 4.4r, +5.2x, - 2 Similarly, for second case In y, =1.2x - 2.6x

In 7 =(-0.6x + 2.6.x – 2x1) +(1– x¡)(-1,8x +5.2x, - 2)<br>In 7, =1.2x - 4.4r, +5.2x, - 2<br>Similarly, for second case<br>In y, =1.2x - 2.6x<br>

Extracted text: In 7 =(-0.6x + 2.6.x – 2x1) +(1– x¡)(-1,8x +5.2x, - 2) In 7, =1.2x - 4.4r, +5.2x, - 2 Similarly, for second case In y, =1.2x - 2.6x

4. The excess Gibbs energy of a binary liquid mixture at T andP is given by;<br>GE<br>= (-1.4x1 – 2.0x2)x1X2<br>RT<br>Show that when these expressions are combined in accord with GE/RT= Exi Inyi the<br>given equation for GF/RT is recovered.<br>

Extracted text: 4. The excess Gibbs energy of a binary liquid mixture at T andP is given by; GE = (-1.4x1 – 2.0x2)x1X2 RT Show that when these expressions are combined in accord with GE/RT= Exi Inyi the given equation for GF/RT is recovered.

Jun 10, 2022

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In 7 =(-0.6x + 2.6.x – 2x1) +(1– x¡)(-1,8x +5.2x, - 2) In 7, =1.2x - 4.4r, +5.2x, - 2 Similarly, for second case In y, =1.2x - 2.6x

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