In 7 =(-0.6x + 2.6.x – 2x1) +(1– x¡)(-1,8x +5.2x, - 2) In 7, =1.2x - 4.4r, +5.2x, - 2 Similarly, for second case In y, =1.2x - 2.6x

In 7 =(-0.6x + 2.6.x – 2x1) +(1– x¡)(-1,8x +5.2x, - 2)<br>In 7, =1.2x - 4.4r, +5.2x, - 2<br>Similarly, for second case<br>In y, =1.2x - 2.6x<br>

Extracted text: In 7 =(-0.6x + 2.6.x – 2x1) +(1– x¡)(-1,8x +5.2x, - 2) In 7, =1.2x - 4.4r, +5.2x, - 2 Similarly, for second case In y, =1.2x - 2.6x

The excess Gibbs energy of a binary liquid mixture at T and P is given by;<br>GE<br>= (-1,4x, – 2.0x2)x1x2<br>RT<br>O Show that (dln vi/dx1)xl-1= (dln v2/dx1)xl-0=0.<br>

Extracted text: The excess Gibbs energy of a binary liquid mixture at T and P is given by; GE = (-1,4x, – 2.0x2)x1x2 RT O Show that (dln vi/dx1)xl-1= (dln v2/dx1)xl-0=0.

Jun 09, 2022

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In 7 =(-0.6x + 2.6.x – 2x1) +(1– x¡)(-1,8x +5.2x, - 2) In 7, =1.2x - 4.4r, +5.2x, - 2 Similarly, for second case In y, =1.2x - 2.6x

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