Implement the quadratic_formula() function. The function takes 3 arguments, a, b, and c, and computes the two results of the quadratic formula: x1=−b+b2−4ac2a x2=−b−b2−4ac2a The quadratic_formula()...


Implement the quadratic_formula() function. The function takes 3 arguments, a, b, and c, and computes the two results of the quadratic formula:



x1=−b+b2−4ac2a

x2=−b−b2−4ac2a


The quadratic_formula() function returns the tuple (x1, x2). Ex: When a = 1, b = -5, and c = 6, quadratic_formula() returns (3, 2).


Code provided in main.py reads a single input line containing values for a, b, and c, separated by spaces. Each input is converted to a float and passed to the quadratic_formula() function.


Ex: If the input is:


2 -3 -77


the output is:


Solutions to 2x^2 + -3x + -77 = 0 x1 = 7 x2 = -5.50


code:


# TODO: Import math module


def quadratic_formula(a, b, c):
# TODO: Compute the quadratic formula results in variables x1 and x2
return (x1, x2)


def print_number(number, prefix_str):
if float(int(number)) == number:
print("{}{:.0f}".format(prefix_str, number))
else:
print("{}{:.2f}".format(prefix_str, number))


if __name__ == "__main__":
input_line = input()
split_line = input_line.split(" ")
a = float(split_line[0])
b = float(split_line[1])
c = float(split_line[2])
solution = quadratic_formula(a, b, c)
print("Solutions to {:.0f}x^2 + {:.0f}x + {:.0f} = 0".format(a, b, c))
print_number(solution[0], "x1 = ")
print_number(solution[1], "x2 = ")



Jun 02, 2022
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