Extracted text: If the time of initial maneuver is (5 sec.), the time of passing vehicle occupies the left lane is (11 sec ), average acceleration is (3.5 km/hr/sec.) ,speed of passing vehicle is (80km/hr) and the speed of the slow vehicle ahead is (45 km/hr), Calculate the Minimum Passing Sight distance (P.S.D.). * P.S.D. = 436.43 m %3D P.S.D. = 563.12 m P.S.D. = 425.25 m P.S.D. = 542.44 m P.S.D. = 453.68 m This is a required question