I saw a problem in StackOverflow. I tried to solve it differently but wasn't able to solve it. This was the problem. You are given an array (which will have a length of at least 3 but could be very...

I saw a problem in StackOverflow. I tried to solve it differently but wasn't able to solve it.

This was the problem.

You are given an array (which will have a length of at least 3 but could be very large) containing integers. The array is either entirely comprised of odd integers or entirely comprised of even integers except for a single integer N. Write a function that takes the array as an argument and returns this “outlier” N.



and I wrote the following code.. still, it didn't work

public class Outlier


{


public static void main(String[] args)


{


int[] x = new int [args.length];



for(int i=0; i


x[i] = Integer.parseInt(args[i]);


}


System.out.print(unique(x)); }




public static int[] unique(int[] x) {




int even = 0;


int odd = 0;


int N = 0;


int[] a = new int [x.length];


for (int i = 0; i < x.length;="" i++)="">


if (x[i] % 2 ==0) {


even ++;


}


else odd ++;


}

for (int i = 0; i < x.length;="" i++)="">


if (odd > even) {


if (x[i] % 2 == 0) {


N = x[i];


for (int j = 0; j


}


}


else if (even > odd ) {


if (x[i] % 2 == 1) {


N = x[i];


for (int j = 0; j


}


}


}


return a;

}


}