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Q1. Reconstructing the figure of rectangular solid –
We have to find distance AB.
Given,
AD=a, DC=b
and CB=c
In triangle ADC, CD is perpendicular to AD.
Hence ADC is right angle triangle.
Hence from Pythagoras theorem,
AC=√ √
Again, now in triangle ACB, BC (height) is perpendicular to AC (base).
Hence ACB is right angle triangle.
Hence from Pythagoras theorem,
AB=√ √(√ )

=√
AB=√ √
Q2.
Using Pseudo-quadratic equation,
Let
Now equation is
Hence t=-3, 4
Now putting back
Hence only solution is
Or
Q3.
By definition of log, x>0 and x
Converting equation on base 10 using formula





Using Pseudo-quadratic equation,
Let log
Now putting value of
Quadratic equation will be
By discriminant method Roots are
√


Where a=1, b=-2.107 and c =1.079
Roots are t=1.115 and 0.992
Now putting back
Solutions are
And
Q4.
In new cosine function, three types of transformations are observed-
1) Compression along vertical axis
2) Vertical downward shift
3) Compression along Horizontal axis
4) Horizontal rightward shift
1) Compression along vertical axis – After compression along vertical
axis,...