ISD 599/MFG 599 XXXXXXXXXXHomework No. 1 Module 3: SMART PRODUCTION SYSTEMS XXXXXXXXXXDue Feb 10, 2023 ...

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Answered 1 days AfterFeb 13, 2023

Answer To: ISD 599/MFG 599 ...

Dr Shweta answered on Feb 15 2023
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Ans 1. The efficiency of machine is calculated as:
e = 1/1+ [Tdown/(1+ά) Tup]
here, ά is the factor by which uptime is increased and downtime is de
creased
ά > 1
According to the preceding equation, efficiency can be increased by either increasing the machine's uptime or decreasing its downtime.
Either an increase in uptime (Tup) or a decrease in downtime (Tdown) has the same effect on the efficiency of a single machine, i.e., both have the same effect.
Ans 2. The reversibility law states that maximum throughput is achieved when each machine's production rate equals the buffer's consumption rate. The total throughput of all machines and buffers should equal the output rate. If we wish to maximize system efficiency, we should replace the machine with the slowest output rate. Doing so guarantees that the replacement machine's output will grow by the same amount as the buffer's use. Thus, system throughput will grow while parts retain stable flow rates. This method assumes steady state production with consistent input and output rates. The reversibility law calculates throughput maximisation in this circumstance. If we can enhance the output of one of the machines by switching it out for a more powerful model, we can better distribute the system's inputs and outputs and achieve maximum throughput. In order to decide which equipment should be replaced, we need to find the machine with the slowest output rate. In order to maximize the system's throughput, we will replace...
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