I need these problems done, show all work, I attach copy of each page of problems ·p. 27 #97,p. 37 #101, ·p. 60 #78, ·p. 63 #45, #63, ·p. 76 #57 ·p.

p. 27 #97:
sin(270O + n .360O)
=> sin(270O + n .360O) = sin(270O)
= sin(180O + 90O)
= -sin( 90O)
=-1
Therefore sin(270O + n .360O) = -1
p. 37 #101:
tan(3θ-4O) = 1/cot(5θ-8O)
 tan(3θ-4O) = tan(5θ-8O)
 nᴨ +3θ-4O = 5θ-8O
 2θ - 4O = nᴨ
 θ = (nᴨ + 4O)/2
 if n=0 then θ = 2O
p. 60 #78:



a) h = 1.9ft; ;
;
and S = 336ft

( )
...