I am learning C for a class I am taking and a homework assignment asks us to makes a list of integers, divides the list into a number of segments, and displays each segment in reverse order. We need...

I am learning C for a class I am taking and a homework assignment asks us to makes a list of integers, divides the list into a number of segments, and displays each segment in reverse order. We need to use the function malloc to dynamically allocate locations for variables a and b. The full assignment is below. I am not too familiar with C and I don't know how to split the list into two arrays.

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Extracted text: AutoSave Project 5 Compatibility Mode OFF Home Insert Draw Design Layout References Mailings Review View Tell me 2 Share O Comments Times New... v 14 A A Аa v A AaBbCcDdEe AaBbCcD AaBbCcDdE AaBbCcDdF AaBbCcD AaBbCcDdEe > ev A v No Spacing Paste Emphasis Normal Strong Subtitle Title Styles Pane B U v ab x, A Heading 1 Dictate Project #5 The purpose of this project is to get familiar with the programming language C to be able to learn the next lectures. The following Java program makes a list of integers, divides the list into a number of segments, and displays each segment in reverse order. Convert the program to a C program. Use the built-in function: malloc to dynamically allocate locations for variables: a and b. import java.til.Bandem; public class Main { public static void main(String[] args){ int[] a; int[] b; Random r = new Random(Şystem.curcenttieMillis()); int alength = CiextInt(10) + 90; int blength = aoextInt(10) + 10; while(alength % blength != 0) alengtb++; a = new int[alenstb]; b = new int[blengtb]; for(int i = 0; i < audength;="" i++)="" a[i]="aextInt(10);" erintterwacd(a);="" for="" (int="" index="0;" index="">< andength;="" ){="" for(int="" į="0;" i="">< bedensth;="" i++)="" b[i]="a[indexti];" brintkaskward(b);="" index="" +="bulength;" }="" }="" 9;="" 2;="" making="" alength="" divisible="" by="" blength="" private="" static="" void="" printbaskward(int[]="" x)="" {="" for(int="" i="Xength" sxsten.qut.rcint(x[¿]="" +="" ".="" susten="" qut.brintla();="" }="" 1;="" i="">= 0; j--) "); - private static void printforward(int[] x) { for(int i = 0; i < xulength; i++) sustem.qut rcint(x[i] + sustem.auturrintla(); } } ", "); answer: page 1 of 1 204 words e english (united states) e3 focus 107% xulength;="" i++)="" sustem.qut="" rcint(x[i]="" +="" sustem.auturrintla();="" }="" }="" ",="" ");="" answer:="" page="" 1="" of="" 1="" 204="" words="" e="" english="" (united="" states)="" e3="" focus="">