Hugo averages 78 words per minute on a typing test with a standard deviation of 5.5 words per minute. Suppose Hugo's words per minute on a typing test are normally distributed. Let X= the number of words per minute on a typing test. Then, X∼N(78,5.5).Suppose Hugo types 61 words per minute in a typing test on Wednesday. The z-score when x=61 is ________. This z-score tells you that x=61 is ________ standard deviations to the ________ (right/left) of the mean, ________.Correctly fill in the blanks in the statement above.
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Suppose Hugo types 61 words per minute in a typing test on Wednesday. The z-score when x=61 is −3.091. This z-score tells you that x=61 is 3.091 standard deviations to theleftof the mean, 78.
Suppose Hugo types 61 words per minute in a typing test on Wednesday. The z-score when x=61 is 3.091. This z-score tells you that x=61 is 3.091 standard deviations to therightof the mean, 78.
Suppose Hugo types 61 words per minute in a typing test on Wednesday. The z-score when x=61 is 2. This z-score tells you that x=61 is 2 standard deviations to therightof the mean, 78.
Suppose Hugo types 61 words per minute in a typing test on Wednesday. The z-score when x=61 is −2. This z-score tells you that x=61 is 2 standard deviations to theleftof the mean, 78.
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