How did he get the value of 4.7? And how did he get the value inside the circle, and is it true or false? ratio of SNR value over the absolute maximum value of an analog signal (xrms\XImax). We have...


How did he get the value of 4.7?<br>And how did he get the value inside<br>the circle, and is it true or false?<br>ratio of SNR value over the absolute maximum value<br>of an analog signal (xrms\XImax).<br>We have to determine SNR in terms of m bits.<br>Step 2 of 3:)<br>>The signal to quantization noise power ratio<br>E(x*)<br>E(c;)<br>SNR =<br>> Relationship between SNR, xrms and step size is defined as<br>SNR = 10.79 + 20- logo<br>where x= RMS value of the signal to be quantized x.<br>Xmas -Xmin<br>2x<br>A=<br>2
Substituting A in Equation D SNR =10.79+20- log10 12" =10.79 + 20 - log0 20m log 2-20log,, 2 Imax =10.79 + 20- logo 20m (0.3010)- 6.02 "Imax SNR = 4.77 + 20- log1o Xpms+6.02m Imax Step 3 of 3:) SNR. =4.77 + 20- log, -6.02m "/>
Extracted text: How did he get the value of 4.7? And how did he get the value inside the circle, and is it true or false? ratio of SNR value over the absolute maximum value of an analog signal (xrms\XImax). We have to determine SNR in terms of m bits. Step 2 of 3:) >The signal to quantization noise power ratio E(x*) E(c;) SNR = > Relationship between SNR, xrms and step size is defined as SNR = 10.79 + 20- logo where x= RMS value of the signal to be quantized x. Xmas -Xmin 2x A= 2" > Substituting A in Equation D SNR =10.79+20- log10 12" =10.79 + 20 - log0 20m log 2-20log,, 2 Imax =10.79 + 20- logo 20m (0.3010)- 6.02 "Imax SNR = 4.77 + 20- log1o Xpms+6.02m Imax Step 3 of 3:) SNR. =4.77 + 20- log, -6.02m

Jun 11, 2022
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