How did he get the value inside the circle? It is possible to explain step by step and how he got the output, the indicator in green Y(F) = 12000 S(F +3000) + 12000 6(f-3000) +D 000 S(F+2010)+ 20000 8...

How did he get the value inside the circle?<br>It is possible to explain step by step<br>and how he got the output, the<br>indicator in green<br>Y(F) = 12000 S(F +3000) + 12000 6(f-3000) +D 000 S(F+2010)+<br>20000 8 (f-2o0)<br>* YE 24000<br>SCF-3000) +24000 S(f+3000) +<br>2.<br>y0 000 S(F-2000) + 40000 S(f+2000)<br>2.<br>2<br>> YF) =<br>> YE)*<br>24000 S(F-3000) + SIf+3000) +<br>%3D<br>2<br>[s(^2000) + 6(f+200)<br>400 00<br>S(f+2000)<br>Step 2 of 2:)<br>we<br>know that<br>Ac cos(27TFct) <<br>Foudier<br>TransFom Ac SCF-fc)+ S(F+F)<br>APply<br>Inverse T8omSFOom to 4(F) we get<br>y (t) = 24000 Cos (21TX 3000 t) + 40000 COs(2T X 200ot)<br>=> yE) = 24000cos (G000TTE) + 4000 CoS (4000 TTE)<br>%3D<br>

Extracted text: How did he get the value inside the circle? It is possible to explain step by step and how he got the output, the indicator in green Y(F) = 12000 S(F +3000) + 12000 6(f-3000) +D 000 S(F+2010)+ 20000 8 (f-2o0) * YE 24000 SCF-3000) +24000 S(f+3000) + 2. y0 000 S(F-2000) + 40000 S(f+2000) 2. 2 > YF) = > YE)* 24000 S(F-3000) + SIf+3000) + %3D 2 [s(^2000) + 6(f+200) 400 00 S(f+2000) Step 2 of 2:) we know that Ac cos(27TFct) < foudier="" transfom="" ac="" scf-fc)+="" s(f+f)="" apply="" inverse="" t8omsfoom="" to="" 4(f)="" we="" get="" y="" (t)="24000" cos="" (21tx="" 3000="" t)="" +="" 40000="" cos(2t="" x="" 200ot)=""> yE) = 24000cos (G000TTE) + 4000 CoS (4000 TTE) %3D

Jun 11, 2022

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How did he get the value inside the circle? It is possible to explain step by step and how he got the output, the indicator in green Y(F) = 12000 S(F +3000) + 12000 6(f-3000) +D 000 S(F+2010)+ 20000 8...

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