Hot combustion gases enter the nozzle of a turbojet engine at 260 kPa, 747°C, and 80 m/s, and they exit at a pressure of 85 kPa. Assuming an isentropic efficiency of 92 percent and treating the...


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Hot combustion gases enter the nozzle of a turbojet<br>engine at 260 kPa, 747°C, and 80 m/s, and they exit at a<br>pressure of 85 kPa. Assuming an isentropic efficiency of<br>92 percent and treating the combustion gases as air, determine<br>(a) the exit velocity and (b) the exit temperature.<br>260 kPa<br>Nozzle<br>747°C<br>85 kPa<br>7N = 92%<br>80 m/s<br>FIGURE P7–132<br>

Extracted text: Hot combustion gases enter the nozzle of a turbojet engine at 260 kPa, 747°C, and 80 m/s, and they exit at a pressure of 85 kPa. Assuming an isentropic efficiency of 92 percent and treating the combustion gases as air, determine (a) the exit velocity and (b) the exit temperature. 260 kPa Nozzle 747°C 85 kPa 7N = 92% 80 m/s FIGURE P7–132

Jun 11, 2022
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