STAT 200 Week 4 Homework Problems Kayla Johnson 6.1.2 1.) The commuter trains on the Red Line for the Regional Transit Authority (RTA) in Cleveland, OH, have a waiting time during peak rush hour...

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Homework problems sheet attached along with part two of another assignment. I attached part one that was done previously because it will be needed for part two. At the end of part one I added the feedback I received.


STAT 200 Week 4 Homework Problems Kayla Johnson 6.1.2 1.) The commuter trains on the Red Line for the Regional Transit Authority (RTA) in Cleveland, OH, have a waiting time during peak rush hour periods of eight minutes ("2012 annual report," 2012). a.) State the random variable. b.) Find the height of this uniform distribution. c.) Find the probability of waiting between four and five minutes. d.) Find the probability of waiting between three and eight minutes. e.) Find the probability of waiting five minutes exactly. 6.3.2 Find the z-score corresponding to the given area. Remember, z is distributed as the standard normal distribution with mean of and standard deviation . a.) The area to the left of z is 15%. b.) The area to the right of z is 65%. c.) The area to the left of z is 10%. d.) The area to the right of z is 5%. e.) The area between and z is 95%. (Hint draw a picture and figure out the area to the left of the .) f.) The area between and z is 99%. 6.3.4 According to the WHO MONICA Project the mean blood pressure for people in China is 128 mmHg with a standard deviation of 23 mmHg (Kuulasmaa, Hense & Tolonen, 1998). Assume that blood pressure is normally distributed. a.) State the random variable. b.) Find the probability that a person in China has blood pressure of 135 mmHg or more. c.) Find the probability that a person in China has blood pressure of 141 mmHg or less. d.) Find the probability that a person in China has blood pressure between 120 and 125 mmHg. e.) Is it unusual for a person in China to have a blood pressure of 135 mmHg? Why or why not? f.) What blood pressure do 90% of all people in China have less than? 6.3.8 A dishwasher has a mean life of 12 years with an estimated standard deviation of 1.25 years ("Appliance life expectancy," 2013). Assume the life of a dishwasher is normally distributed. a.) State the random variable. b.) Find the probability that a dishwasher will last more than 15 years. c.) Find the probability that a dishwasher will last less than 6 years. d.) Find the probability that a dishwasher will last between 8 and 10 years. e.) If you found a dishwasher that lasted less than 6 years, would you think that you have a problem with the manufacturing process? Why or why not? f.) A manufacturer of dishwashers only wants to replace free of charge 5% of all dishwashers. How long should the manufacturer make the warranty period? 6.3.10 The mean yearly rainfall in Sydney, Australia, is about 137 mm and the standard deviation is about 69 mm ("Annual maximums of," 2013). Assume rainfall is normally distributed. a.) State the random variable. b.) Find the probability that the yearly rainfall is less than 100 mm. c.) Find the probability that the yearly rainfall is more than 240 mm. d.) Find the probability that the yearly rainfall is between 140 and 250 mm. e.) If a year has a rainfall less than 100mm, does that mean it is an unusually dry year? Why or why not? f.) What rainfall amount are 90% of all yearly rainfalls more than? 6.4.4 Annual rainfalls for Sydney, Australia are given in table #6.4.6. ("Annual maximums of," 2013). Can you assume rainfall is normally distributed? Table #6.4.6: Annual Rainfall in Sydney, Australia 146.8 383 90.9 178.1 267.5 95.5 156.5 180 90.9 139.7 200.2 171.7 187.2 184.9 70.1 58 84.1 55.6 133.1 271.8 135.9 71.9 99.4 110.6 47.5 97.8 122.7 58.4 154.4 173.7 118.8 88 84.6 171.5 254.3 185.9 137.2 138.9 96.2 85 45.2 74.7 264.9 113.8 133.4 68.1 156.4 6.5.2 A random variable is normally distributed. It has a mean of 245 and a standard deviation of 21. a.) If you take a sample of size 10, can you say what the shape of the distribution for the sample mean is? Why? b.) For a sample of size 10, state the mean of the sample mean and the standard deviation of the sample mean. c.) For a sample of size 10, find the probability that the sample mean is more than 241. d.) If you take a sample of size 35, can you say what the shape of the distribution of the sample mean is? Why? e.) For a sample of size 35, state the mean of the sample mean and the standard deviation of the sample mean. f.) For a sample of size 35, find the probability that the sample mean is more than 241. g.) Compare your answers in part c and f. Why is one smaller than the other? 6.5.4 According to the WHO MONICA Project the mean blood pressure for people in China is 128 mmHg with a standard deviation of 23 mmHg (Kuulasmaa, Hense & Tolonen, 1998). Blood pressure is normally distributed. a.) State the random variable. b.) Suppose a sample of size 15 is taken. State the shape of the distribution of the sample mean. c.) Suppose a sample of size 15 is taken. State the mean of the sample mean. d.) Suppose a sample of size 15 is taken. State the standard deviation of the sample mean. e.) Suppose a sample of size 15 is taken. Find the probability that the sample mean blood pressure is more than 135 mmHg. f.) Would it be unusual to find a sample mean of 15 people in China of more than 135 mmHg? Why or why not? g.) If you did find a sample mean for 15 people in China to be more than 135 mmHg, what might you conclude? 6.5.6 The mean cholesterol levels of women age 45-59 in Ghana, Nigeria, and Seychelles is 5.1 mmol/l and the standard deviation is 1.0 mmol/l (Lawes, Hoorn, Law & Rodgers, 2004). Assume that cholesterol levels are normally distributed. a.) State the random variable. b.) Find the probability that a woman age 45-59 in Ghana has a cholesterol level above 6.2 mmol/l (considered a high level). c.) Suppose doctors decide to test the woman’s cholesterol level again and average the two values. Find the probability that this woman’s mean cholesterol level for the two tests is above 6.2 mmol/l. d.) Suppose doctors being very conservative decide to test the woman’s cholesterol level a third time and average the three values. Find the probability that this woman’s mean cholesterol level for the three tests is above 6.2 mmol/l. e.) If the sample mean cholesterol level for this woman after three tests is above 6.2 mmol/l, what could you conclude? 6.5.8 A dishwasher has a mean life of 12 years with an estimated standard deviation of 1.25 years ("Appliance life expectancy," 2013). The life of a dishwasher is normally distributed. Suppose you are a manufacturer and you take a sample of 10 dishwashers that you made. a.) State the random variable. b.) Find the mean of the sample mean. c.) Find the standard deviation of the sample mean. d.) What is the shape of the sampling distribution of the sample mean? Why? e.) Find the probability that the sample mean of the dishwashers is less than 6 years. f.) If you found the sample mean life of the 10 dishwashers to be less than 6 years, would you think that you have a problem with the manufacturing process? Why or why not? µ = 0 m=0 σ = 1 s=1 −z -z STAT200: Assignment #2 - Descriptive Statistics Analysis and Writeup - Instructions Page 1 of 3 STAT200 Introduction to Statistics Assignment #2: Descriptive Statistics Analysis and Writeup Assignment #2: Descriptive Statistics Analysis and Writeup In the first assignment (Assignment #1: Descriptive Statistics Analysis Data Plan), you developed a scenario about annual household expenditures and a plan for analyzing the data using descriptive statistic methods. The purpose of this assignment is to carry out the descriptive statistics analysis plan and write up the results. The expected outcome of this assignment is a two to three page write-up of the findings from your analysis as well as a recommendation. Assignment Steps: Step #1: Review Feedback from Your Instructor Before performing any analysis, please make sure to review your instructor’s feedback on Assignment #1: Descriptive Statistics Data Analysis Plan. Based on the feedback, modify variables, tables, and selected statistics, graphs, and tables, if needed. Step #2: Perform Descriptive Statistic Analysis  Task 1: Look at the dataset. • (Re)Familiarize yourself with the variables. Review Table 1: Variables Selected for the Analysis you generated for the first assignment as well as your instructor’s feedback. In addition, look at the data dictionary contained in the data set for information about the variables. • Select the variables you need for the analysis.  Task 2: Complete your data analysis, as outlined in your first assignment, with any needed modifications, based on your instructor’s feedback. • Calculate Measures of Central Tendency and Variability. Use the information from Assignment #1 - Table 2. Numerical Summaries of the Selected Variables. Here again, be sure to see your instructor’s feedback and incorporate into the analysis. • Prepare Graphs and/or Tables. Use the information from Assignment #1 - Table 3. Type of Graphs and/or Tables for Selected Variables. Here again, be sure to see your instructor’s feedback and incorporate into the analysis. STAT200: Assignment #2 - Descriptive Statistics Analysis and Writeup - Instructions Page 2 of 3 Step #3: Write-up findings using the Provided Template For this part of the assignment, write a short 2-3 page write-up of the process you followed and the findings from your analysis. You will describe, in words, the statistical analysis used and present the results in both statistical/text and graphic formats. Here are the main sections for this assignment: ✓ Identifying Information. Fill in information on name, class, instructor, and
Answered Same DayFeb 06, 2021

Answer To: STAT 200 Week 4 Homework Problems Kayla Johnson 6.1.2 1.) The commuter trains on the Red Line for...

Pooja answered on Feb 08 2021
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STAT 200 Week 4 Homework Problems
Kayla Johnson
6.1.2
1.) The commuter trains on the Red Line for the Regional Transit Authority (RTA) in Cleveland, OH, have a waiting time during peak rush hour periods of eight minutes ("2012 annual report," 2012).
a.) State the random variable
.
x=waiting time during peak hours
b.) Find the height of this uniform distribution.
1/(8-0)=0.125
c.) Find the probability of waiting between four and five minutes.
P(4d.) Find the probability of waiting between three and eight minutes.
P(3e.) Find the probability of waiting five minutes exactly.
P(x=5) = 0*0.125 = 0.000
6.3.2
Find the z-score corresponding to the given area. Remember, z is distributed as the standard normal distribution with mean of and standard deviation .
a.) The area to the left of z is 15%.
=NORMINV(0.15,0,1)= -1.036
b.) The area to the right of z is 65%.
=NORMINV (0.35,0,1)= -0.385
c.) The area to the left of z is 10%.
=NORMINV(0.1,0,1)= -1.282
d.) The area to the right of z is 5%.
=NORMINV(0.95,0,1)= 1.645
e.)
The area between and z is 95%. (Hint draw a picture and figure out the area to the left of the .)
= NORMSINV(0.95) = -1.645
f.)
The area between and z is 99%.
=NORMSINV(0.99) = -2.326
6.3.4
According to the WHO MONICA Project the mean blood pressure for people in China is 128 mmHg with a standard deviation of 23 mmHg (Kuulasmaa, Hense & Tolonen, 1998). Assume that blood pressure is normally distributed.
a.) State the random variable.
x=blood pressure for people in China.
b.) Find the probability that a person in China has blood pressure of 135 mmHg or more.
normalcdf(135,1e99,128,23) = 0.3804
c.) Find the probability that a person in China has blood pressure of 141 mmHg or less.
normalcdf(-1e99,141,128,23) = 0.714
d.) Find the probability that a person in China has blood pressure between 120 and 125 mmHg.
normalcdf(120,125,128,23) = 0.0841
e.) Is it unusual for a person in China to have a blood pressure of 135 mmHg? Why or why not?
From question b., it is unusual because the probability of blood pressure of 135 mmHg or more is less than 5%.
f.) What blood pressure do 90% of all people in China have less than?
=norminv(0.9,128,23) = 157.476
6.3.8
A dishwasher has a mean life of 12 years with an estimated standard deviation of 1.25 years ("Appliance life expectancy," 2013). Assume the life of a dishwasher is normally distributed.
a.) State the random variable.
x= life expectancy of a dishwasher
b.) Find the probability that a dishwasher will last more than 15 years.
normalcdf(15,1e99,12,1.25) = 0.008
c.) Find the probability that a dishwasher will last less than 6 years.
normalcdf(-1e99,6,12,1.25) = 0
d.) Find the probability that a dishwasher will last between...
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