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Q1)
Ho: average weight is 2.88 ounces. That is u = 2.88
H1: average weight is not 2.88 ounces. That is u =/= 2.88

Table 1
One-Sample Statistics
N Mean Std. Deviation Std. Error Mean
VAR00001 20 2.9270 .39247 .08776

Table 2
One-Sample Test
Test Value = 2.88
t df Sig. (2-tailed) Mean Difference 95% Confidence Interval of the
Difference
Lower Upper
VAR00001 .536 19 .598 .04700 -.1367 .2307
From table 2, t = 5.39 and p-value is .598 which is greater than set level of significance, alpha =
0.05. Hence I fail to reject null hypothesis at 5% level of significance and conclude that average
weight is 2.88 ounces. That is u = 2.88.
Hence there is no sufficient evidence to support the hypothesis that machine is malfunctioning.
Q2)
Ho: there is no significant difference in the money held in individual savings accounts for males
and females. That is u1 = u2
H1: there is significant difference in the money held in individual savings accounts for males and
females. That is u1 =/= u2
Table 3
Group Statistics
sex N Mean Std. Deviation Std. Error Mean
money
male 12 8052.4167 2151.60057 621.11358
female 12 7579.1667 2152.10873 621.26028

Table 4
Independent Samples Test
Levene's
Test for
Equality of
Variances
t-test for Equality of Means
F Sig. t df Sig.
(2-
tailed)
Mean
Difference
Std. Error
Difference
95% Confidence Interval of
the Difference
Lower Upper
money
Equal
variances
assumed
.008 .931 .539 22 .595 473.25000 878.49099 -1348.62880 2295.12880
Equal
variances
not
assumed
.539 22.000 .595 473.25000 878.49099 -1348.62880 2295.12880
From table 4, t = .539and p-value is .595 which is greater than...