Hi! The question is in bold/underlined. The answers in Direction 1 an 2 are also attached for reference. Thank you! Direction1. Construct a Frequency Distribution Table for the above-given data. 1.1...

Hi! The question is in bold/underlined. The answers in Direction 1 an 2 are also attached for reference. Thank you!


Direction1. Construct a Frequency Distribution Table for the above-given data.
1.1 Provide the title for the table and write 1 as the table number.
1.2 Fill-in Column 1 Class Interval. Use 10 class intervals.
Column 2 Class Boundaries
Column 3 Class Marks
Column 4 Frequency
1.3 Show solutions for finding the range, class size, and the lowest class
mark.

Direction 2. Continue constructing the table by adding

Column 5 Cumulative Frequency with cf
Column 6 Cumulative Percentage Frequency with cpf
Column 7 Relative Frequency (RF)

Direction 3. Continue constructing the table.

1.1 Add column fXi

1.2 Compute for the mean, the median, and the mode of the given data.




Show your solutions.




1.3 Interpret the results.

Extracted text: DIRECTION 1.1-1.2 LOWEST CLASS MARK = Lower Limit + Upper Limit 2 Frequency Class Boundary 57.5-62.5 62.5-67.5 67.5-72.5 Class Interval Class Mark = 58 + 62 58-62 60 2 63-67 65 68-72 70 5 = 120 73-77 72.5-77.5 75 3 78-82 77.5-82.5 80 4 2 83-87 82.5-87.5 87.5-92.5 92.5-97.5 85 10 88-92 90 9 = 60 93-97 95 6 98-102 97.5-102.5 100 3 103-107 102.5-107.5 105 1 DIRECTION 2 DIRECTION 1.3 Frequency(fi) (cf) 45 (cpf) RF 0.04 0.04 2 4.44 100.00 RANGE = Maximum Value – Minimum Value 8.89 2 4 43 95.56 5 9 41 20.00 91.11 0.11 = 104 – 58 = 46 80.00 73.33 3 12 36 26.67 0.07 4 16 33 35.56 0.09 10 26 29 57.78 64.44 0.22 9 35 19 77.78 42.22 0.20 6 41 10 91.11 22.22 0.13 3 44 4 97.78 8.89 0.07 CLASS SIZE = Range Number of Classes 1 45 1 100.00 2.22 0.02 = 46 10 End of document I = 4.6 = 5