he probability distribution of x , the number of defective tires on a randomly selected automobile checked at a certain inspection station, is given in the following table. x 0 1 2 3 4 p ( x ) 0.56...

he probability distribution ofx, the number of defective tires on a randomly selected automobile checked at a certain inspection station, is given in the following table.

x	0	1	2	3	4
p(x)	0.56	0.17	0.06	0.03	0.18

(a)

Calculate the mean value ofx.

μ_x = tires per car

(b)

Interpret the mean value ofx in the context of a long sequence of observations of number of defective tires.

In repeated inspections of cars at this station, the mean number of defective tires is tires per car.

(c)

What is the probability thatx exceeds its mean value?

P(x > μ_x) =

(d)

Calculate the standard deviation ofx. (Round your answer to four decimal places.)

σ_x = tires per car

Jun 01, 2022

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he probability distribution of x , the number of defective tires on a randomly selected automobile checked at a certain inspection station, is given in the following table. x 0 1 2 3 4 p ( x ) 0.56...

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