1. a) 5% b) 50% c) one fifth of 1% 2. a) z = 1.96 and z = -1.96 b) z = 2.58 and z = -2.58 c) z = 3.29 and z = -3.29 3. a) the area between the scores b) the area in the tails beyond each score 4. a) z...

1. a) 5% b) 50% c) one fifth of 1%

2. a) z = 1.96 and z = -1.96 b) z = 2.58 and z = -2.58 c) z = 3.29 and z = -3.29

3. a) the area between the scores b) the area in the tails beyond each score

4. a) z = 2.58 and z = -2.58 b) z = 1.96 and z = -1.96 c) z = 3.29 and z = -3.29

5. a) not in b) in

6. a) cannot b) can

7. a) can b) cannot

Extracted text: he


Extracted text: Standard Normal Distribution Mean 0.0 Standard Deviation = 1.0 5000 2500 -3 -2 -1 1. -0.67 0.67 The critical region is The z-score boundaries for an alpha level a = 0.001 are: %3D Z = 2.58 and z = -2.58 Oz = 1.96 and z = -1.96 Oz= 3.29 and z = -3.29 Suppose that the calculated z statistic for a particular hypothesis test is 4.16 and the alpha is 0.001. This z statistic is the critical region. Therefore, the researcher reject the null hypothesis, and he conclude the alternative hypothesis is probably correct.