Having trouble with question 1c) 1)You need to construct a confidence interval to see which employees are not happy with a policy. You took a simple random sample of 17 employees out of 134. Construct...



Having trouble with question 1c)


1)You need to construct a confidence interval to see which employees are not happy with a policy.  You took a simple random sample of 17 employees out of 134.  Construct the confidence interval for the population proportion.  Use the formula for this one. Use a significance level of 98%.


1a) The critical value is (3 decimals like 2.187)=
2.326


1b) The margin of error is (use 3 decimals for every number on the formula) (3 decimals: .084)
=.067



1c) The confidence interval is (  ,  )  (first one has two decimals .01, the second one three decimals .273)



1d) The opinion was that the real number for all employees is 30%.




What can you conclude from the result that you got from part C? =
It is definitely not 30%





Jun 08, 2022
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