Grammar Rule Semantic Rules S- exp еxp.etype D if exp.isFloat then float else int S.val - exp.val exp, .isFloat = exp2 .isFloat or exp, .isFloat exp2 .etype = exp .etype exp3 .etype - exp, .etype...

1. 
   Draw dependency graphs corresponding to each grammar rule (given in the below table) and for expression 7/4/3.0
   
   


2. 
   
   Describe the two passes needed to compute the attributes on the syntax tree of 7/4/3.0, including a possible order in which the nodes could be visited and the attribute values computed at each point.
   

Extracted text: Grammar Rule Semantic Rules S- exp еxp.etype D if exp.isFloat then float else int S.val - exp.val exp, .isFloat = exp2 .isFloat or exp, .isFloat exp2 .etype = exp .etype exp3 .etype - exp, .etype exp,.val = if exp, .etype - int then exp, .val div exps .val else expz .val / exp3 .val exp.isFloat = false exp.val = if exp.etype = int then num.val else Float(num.val) exp.isFloat = true exp.val = num.num.val exp, - expz / exp3 exp + num exp num.num