Given the following code, what does the "cast" do? int g; g = (int) 19.676; Force the value 19.676 to be converted into an int value (which will be stored in g) by rounding up to the next integer...

Extracted text: Given the following code, what does the "cast" do? int g; g = (int) 19.676; Force the value 19.676 to be converted into an int value (which will be stored in g) by rounding up to the next integer (i.e. 20) Force the value 19.676 to be converted into an int value (which will be stored in g) by rounding to the nearest integer Force the value 19.676 to be converted into an int value (which will be stored in g) by truncating to an integer (i.e. 19) Force the variable g to change type from int to double to accept and store the value 19.546 OO0O