Given in the following table is the result of the standard proctor test: Dry Unit Weight (KN/m³) 16.79 Test no. Water Content (%) 5.75 1 2 8.60 19.20 3 13.7 19.28 4 16.8 16.99 5 21.3 15.50 Then...


Given in the following table is the result of the standard proctor test:<br>Dry Unit Weight<br>(KN/m³)<br>16.79<br>Test no.<br>Water Content<br>(%)<br>5.75<br>1<br>2<br>8.60<br>19.20<br>3<br>13.7<br>19.28<br>4<br>16.8<br>16.99<br>5<br>21.3<br>15.50<br>Then followed by a sand cone test has been performed in a compacted fill which has<br>the following data:<br>Initial mass of sand cone apparatus with sand = 5.915 kg<br>Final mass of sand cone apparatus with sand = 2.380 kg<br>Mass of soil removed from hole = 2.883 kg<br>Moisture content of soil from hole = 7%<br>Density of sand =1300 kg/m³<br>Volume of sand cone below valve = 0.001114 m³<br>a) Using compaction curve, plot the water content versus the dry unit weight to<br>determine the maximum dry unit weight and the optimum moisture content<br>b) Determine the field dry unit weight in KN/m³<br>c) Determine the relative compaction and rate its quality<br>

Extracted text: Given in the following table is the result of the standard proctor test: Dry Unit Weight (KN/m³) 16.79 Test no. Water Content (%) 5.75 1 2 8.60 19.20 3 13.7 19.28 4 16.8 16.99 5 21.3 15.50 Then followed by a sand cone test has been performed in a compacted fill which has the following data: Initial mass of sand cone apparatus with sand = 5.915 kg Final mass of sand cone apparatus with sand = 2.380 kg Mass of soil removed from hole = 2.883 kg Moisture content of soil from hole = 7% Density of sand =1300 kg/m³ Volume of sand cone below valve = 0.001114 m³ a) Using compaction curve, plot the water content versus the dry unit weight to determine the maximum dry unit weight and the optimum moisture content b) Determine the field dry unit weight in KN/m³ c) Determine the relative compaction and rate its quality

Jun 11, 2022
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