given function 'newsort', consider a and b newsort (array, a,b): if array[a] > array[b] Exchange array[a] array[b] if (a + 1)>= b return k

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given function 'newsort', consider a and b<br>newsort (array, a,b):<br>if array[a] > array[b]<br>Exchange array[a] <-> array[b]<br>if (a + 1)>= b<br>return<br>k<- int((b-a+1)/3) # the

Extracted text: given function 'newsort', consider a and b newsort (array, a,b): if array[a] > array[b] Exchange array[a] <-> array[b] if (a + 1)>= b return k<- int((b-a+1)/3)="" #="" the="" "int"="" function="" acts="" as="" floor="" newsort="" (array,="" a,="" b-k)="" newsort="" (array,="" a+k,="" b)="" newsort="" (array,="" a,="" b-k)="" a)="" does="" this="" 'newsort'="" correctly="" sort="" the="" array?="" why?="" b)="" find="" a="" recurrence="" for="" newsort(t(n)="">

Jun 07, 2022

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given function 'newsort', consider a and b newsort (array, a,b): if array[a] > array[b] Exchange array[a] array[b] if (a + 1)>= b return k

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