Given five inputs ( a , b , c , d , e ) connected to 8051’s port P 1 and P 2 with : P 1 . 0 = a , P 2 . 0 = b , P 1 . 3 = c , P 2 . 7 = d et P 1 . 6 = e . Outputs S 0 and S 1 are connected to P 3 . 0...

1. Given five inputs (a
   , b
   , c
   , d
   , e) connected to 8051’s port
   P
   ₁
   and
   P
   ₂
   with :
   P
   <sub>1
   
   .
   
   0</sub>
   =
   a
   , P
   <sub>2
   
   .
   
   0</sub>
   =
   b
   , P
   <sub>1
   
   .
   
   3</sub>
   =
   c
   , P
   <sub>2
   
   .
   
   7</sub>
   =
   d
   et
   P
   <sub>1
   
   .
   
   6</sub>
   =
   e. Outputs
   S
   ₀
   and
   S
   ₁
   are connected to
   P
   <sub>3
   
   .
   
   0</sub>
   and
   P
   <sub>3
   
   .
   
   1</sub>
   respectively as shown in the figure below. We propose to realize the following logic

S
₀
=a
.b
+
c
.d
+
e
.(a
.b
+
a
.b)

S
₁
=c
.b
+
d
+
e
.a
.b